Work

Work happens when a force causes an object to move. It’s calculated using:

\[ W = F \cdot d \cdot \cos\theta \]

Where:

  • \( F \) = Force applied
  • \( d \) = Displacement
  • \( \theta \) = Angle between force and displacement

When is work not done?

  • 🚫 No displacement: Like pushing a wall that doesn’t move.
  • 🚫 No force: A block sliding freely on a smooth table (no friction).
  • 🚫 Force and displacement are perpendicular: Gravity does no work on a horizontally moving object.

Work can be positive or negative! If \( \theta \) is between 90°–180°, work is negative (e.g., friction opposing motion).

Kinetic Energy

Kinetic energy (\( K \)) is the energy an object has due to its motion:

\[ K = \frac{1}{2}mv^2 \]

Examples:

  • A bullet (50g at 200 m/s) has 1000 J of kinetic energy.
  • If it loses 90% energy, its speed drops to ~63.2 m/s (not 90% slower!).

Work Done by a Variable Force

For changing forces, work is the area under the force-displacement graph. Use integration:

\[ W = \int_{x_i}^{x_f} F(x) \, dx \]

Small displacements (\( \Delta x \)) approximate constant force: \( \Delta W = F(x) \cdot \Delta x \).

Important NEET Concepts

  • Work conditions: When is work zero? (Displacement=0, force=0, or force⊥displacement)
  • Work-Energy Theorem: Negative work (e.g., friction) removes kinetic energy.
  • Kinetic Energy calculations: Use \( K = \frac{1}{2}mv^2 \) for problems like bullet speed changes.
  • Newton’s Third Law & Work: Equal forces don’t mean equal work (e.g., cycle vs. road).

Example Problem (Solved!)

A cyclist skids 10 m. Road applies 200 N backward force. What’s the work done by the road?

Solution:

\[ W = 200 \times 10 \times \cos(180^\circ) = -2000\, \text{J} \]

Negative work = energy lost by the cycle. Road does no work because it doesn’t move!