Why do some reactions zip along while others crawl? ⚡🐢

The speed (rate) of a reaction depends on how often reacting particles bump into each other with enough energy and the right orientation. Four ideas help us predict and control that speed. :contentReference[oaicite:0]{index=0}


1️⃣ Concentration – the starting line-up

Imagine players on a field: the more players, the more collisions. For a general reaction

\( aA + bB \;\longrightarrow\; cC + dD \)

experiments show the rate follows a rate law:

\( \text{Rate} = k\,[A]^x[B]^y \)

  • \(k\) is the rate constant (it changes only with temperature or catalyst).
  • \(x\) and \(y\) tell how strongly the rate depends on each reactant’s concentration. We find them only by experiment, not by the balanced equation. :contentReference[oaicite:1]{index=1}

Example (brown gas formation): Doubling \([NO]\) while keeping \([O_2]\) fixed makes the rate four times faster, so the law is

\( \text{Rate}=k\,[NO]^2[O_2] \)

This shows rate ∝ \([NO]^2\) but only ∝ \([O_2]\). 😎 :contentReference[oaicite:2]{index=2}


2️⃣ Order of reaction – the “power” game 💪

The order is the sum of the exponents in the rate law:

Order = \(x + y\)

So \( \text{Rate}=k[A]^{1/2}[B]^{3/2} \) is second-order, while \( \text{Rate}=k[A]^{3/2}[B]^{-1} \) is half-order! Orders can be 0, 1, 2, fractions… anything the experiment says. :contentReference[oaicite:3]{index=3}

Units of the rate constant help check the order:

OrderUnits of \(k\)
0mol L−1 s−1
1s−1
2L mol−1 s−1

Spotting units like L mol−1 s−1 instantly tells you it’s a second-order reaction. 👌 :contentReference[oaicite:4]{index=4}


3️⃣ Molecularity – counting the collision squad 🤝

Molecularity is the number of particles that collide in a single elementary step:

  • Unimolecular: one particle decomposes, e.g., \( \mathrm{NH_4NO_2 \rightarrow N_2 + 2H_2O} \)
  • Bimolecular: two collide, e.g., \( 2HI \rightarrow H_2 + I_2 \)
  • Termolecular: three collide, e.g., \( 2NO + O_2 \rightarrow 2NO_2 \) (rare)

Key differences:

  • Order comes from experiments; molecularity is just a head-count in a single step.
  • Molecularity is always a whole number (never 0 or a fraction).
  • In complex (multi-step) reactions, only the slowest step decides the overall rate law. :contentReference[oaicite:5]{index=5}

4️⃣ Complex reactions & the slow-step 🐢

Think of a relay race: the slowest runner sets the team’s time. In chemistry, the rate-determining step does the same.

Example: In basic solution, iodide (\(I^-\)) speeds up hydrogen-peroxide breakdown:

  1. \( \mathrm{H_2O_2 + I^- \rightarrow H_2O + IO^-} \) 🐢 (slow)
  2. \( \mathrm{H_2O_2 + IO^- \rightarrow H_2O + I^- + O_2} \) (fast)

Because the first step is slow, the observed rate law is

\( \text{Rate}=k\,[H_2O_2][I^-] \)

The intermediate \(IO^-\) never shows up in the final equation but is crucial during the race! :contentReference[oaicite:6]{index=6}


🚀 Quick recap vs. NEET 🔥

  1. Rate law & order: know how to get the rate law from data and sum exponents.
  2. Units of \(k\): zero (mol L−1 s−1), first (s−1), second (L mol−1 s−1).
  3. Effect of concentration: changing \([A]\) by a factor \(n\) changes rate by \(n^x\).
  4. Order vs. molecularity: experiment vs. collision count, whole vs. fractional.
  5. Rate-determining step: for mechanisms, the slow step’s molecularity = overall order.

Master these five and you’ll breeze through typical kinetics questions on NEET! 🌟