Dimensional Analysis and Its Applications
Dimensions of Physical Quantities
Every physical quantity has dimensions, which describe its nature. These dimensions are based on seven fundamental quantities:
- Length [L]
- Mass [M]
- Time [T]
- Electric current [A]
- Thermodynamic temperature [K]
- Luminous intensity [cd]
- Amount of substance [mol]
For example:
- Volume has dimensions \([L^3]\), because it’s length × breadth × height.
- Force has dimensions \([M L T^{-2}]\), because it’s mass × acceleration (which is length/time²).
Dimensional Formulae and Equations
A dimensional formula shows how a physical quantity is expressed in terms of base dimensions. For example:
- Speed: \([M^0 L T^{-1}]\)
- Acceleration: \([M^0 L T^{-2}]\)
- Mass density: \([M L^{-3} T^0]\)
A dimensional equation equates a physical quantity with its dimensional formula, like:
- \([V] = [M^0 L^3 T^0]\)
- \([F] = [M L T^{-2}]\)
Applications of Dimensional Analysis
1. Checking Dimensional Consistency
An equation must have the same dimensions on both sides. For example, the equation for distance traveled:
\[x = x_0 + v_0 t + \frac{1}{2} \alpha t^2\]
All terms have the dimension of length \([L]\), so the equation is dimensionally correct.
Note: A dimensionally correct equation isn’t necessarily right, but a dimensionally wrong equation is definitely wrong!
2. Deducing Relations Between Quantities
Dimensional analysis can help derive relationships. For example, the time period \(T\) of a simple pendulum depends on:
- Length \(l\)
- Acceleration due to gravity \(g\)
- Mass \(m\) (but it turns out \(m\) doesn’t affect \(T\))
Using dimensions, we find:
\[T = k \sqrt{\frac{l}{g}}\]
where \(k\) is a dimensionless constant (later found to be \(2\pi\)).
Important Concepts for NEET
- Principle of Homogeneity: All terms in an equation must have the same dimensions.
- Dimensional Formulas: Memorize common ones like force \([M L T^{-2}]\), energy \([M L^2 T^{-2}]\), etc.
- Checking Equations: Use dimensional analysis to verify if an equation might be correct.
- Deriving Relations: Understand how to use dimensions to find relationships between physical quantities.
- Limitations: Dimensional analysis can’t determine dimensionless constants or distinguish between quantities with the same dimensions.
Examples
Example 1: Check if \(K = \frac{1}{2}mv^2\) is dimensionally correct.
Left side (kinetic energy \(K\)) has dimensions \([M L^2 T^{-2}]\).
Right side: \([M] \times [L T^{-1}]^2 = [M L^2 T^{-2}]\).
Both sides match, so the equation is dimensionally valid.
Example 2: Why can’t \(K = m^2 v^3\) be correct for kinetic energy?
Dimensions of right side: \([M^2 L^3 T^{-3}]\), which don’t match \([M L^2 T^{-2}]\). So it’s wrong.